Trigonometry, as it suggests, is all about triangles, mostly right-angled triangles. Trigonometry is a system that helps us to work out missing or unknown side lengths or angles in a triangle. **Cos2x** identity is one of the important identities in trigonometry that help us in finding the missing value.

In this article, we are going to look into **cos2x identiy**, its various formula, their derivations and work out some examples to grasp the concept in much better way.

Index

**History**

The Greek mathematician *Hipparchus* produced the first known tables of trigonometry in about 140 BC. Although these tables have not survived, it is claimed that Hipparchus wrote twelve books of tables of chords, making Hipparchus the founder of trigonometry.

**Important Cos2x Identity**

Cos2x identity is one of the important identities in trigonometry that can be expressed in different ways.

Cos2x identity can be expressed in terms of different trigonometric functions such as sine, cosine, and as well in tangent.

- \(\cos(2x) = \cos^2x – \sin^2x\)

- \(\cos(2x) = 2 \cos^2x – 1\)

- \(\cos(2x) = 1 – 2sin^2x\)

- \(\cos(2x) = \frac{1 – tan^2x}{1 + tan^2x}\)

**Derivations** of Cos2x Identity

**1.** \(\cos(2x) = \cos^2x – \sin^2x\)

\begin{array}

\,\,\,\,\,\,\,\, \cos(2x) & = \cos(x + x)\\

\,\,\,\,\,\,\,\, & = \cos(x) \cos(x) – \sin(x) \sin(x)\\

\,\,\,\,\,\,\,\, & = \cos^2x – \sin^2x\\

\end{array}

\)

**2.** \(cos(2x) = 2 \cos^2x – 1\)

\begin{array}

\,\,\,\,\,\,\,\, \cos(2x) & = \cos^2x – \sin^2x\\

\,\,\,\,\,\,\,\, & = \cos^2x – {1 – \cos^2x}\\

\,\,\,\,\,\,\,\, & = 2 \cos^2x – 1\\

\end{array}

\)

**3.** \(\cos(2x) = 1 – 2 \sin^2x\)

\begin{array}

\,\,\,\,\,\,\,\, \cos(2x) & = \cos^2x – \sin^2x\\

\,\,\,\,\,\,\,\, & = {1 – \sin^2x} – \sin^2x\\

\,\,\,\,\,\,\,\, & = 1 – 2 \sin^2x\\

\end{array}

\)

**4.** \(\cos(2x) = \frac{1 – \tan^2x}{1 + \tan^2x}\)

\begin{array}

\,\,\,\,\,\,\,\, \cos(2x) & = \cos^2x – \sin^2x\\

\,\,\,\,\,\,\,\, & = \frac{\cos^2x – \sin^2x}{1}\\

\,\,\,\,\,\,\,\, & = \frac{\cos^2x – \sin^2x}{\cos^2x + \sin^2x}\\

\end{array}\\

\,\,\,\,\,\,\,\, \text{Dividing numerator and denominator with} \cos^2x \\

\begin{array}\\

\,\,\,\,\,\,\,\, \cos(2x) & =\frac{ 1 – \frac{\sin^2x}{\cos^2x}}{1 + \frac{\sin^2x}{\cos^2x}} \\

\,\,\,\,\,\,\,\, & = \frac{1 – \tan^2x}{1 + \tan^2x}\\

\end{array}

\)

**Solved Questions**

**Question 1. Find the value of \(\cos(120)\).**

**Solution.**

\begin{array}

\,\,\,\,\,\,\,\, \cos(120) & = \cos(2(60))\\

\,\,\,\,\,\,\,\, & = \cos^2(60) – \sin^2(60)\\

\,\,\,\,\,\,\,\, & = \frac{1}{2} – \frac{{3}}{4}\\

\,\,\,\,\,\,\,\, & = \frac{-1}{2}\\

\end{array}

\)

**Question 2. Solve \(\cos(2a) = \sin(a)\), for \(-\pi \leq a \leq \pi.\)**

**Solution. **

\(\cos 2a = \sin a\)

\(1 – 2 \sin^2(a) = \sin a\)

\(2 \sin^2(a) + \sin(a) + 1 = 0\)

\((2 \sin(a) – 1)(\sin(a) + 1) = 0\)

Therefore, \(2 \sin(a) = 1\) or \(\sin(a) = (-1)\)

\(\sin(a) = \frac{1}{2}\) (or) \((-1)\)

**FAQs**

**What are the formulas for Cos2x?**The formulas for cos 2x are**1.** cos2x = cos^{2}x – sin^{2}x**2.** cos2x = 2cos^{2}x – 1**3.** cos2x = 1 – 2sin^{2}x

**What is derivative of Cos2x?**Derivative of \(\cos 2x\) is \((-2 \sin2x)\)

**What is the integral of cos2x?**Integral of \(\cos 2x\) is \(\frac{1}{2}sin2x + c\)

**Cos2x formula in tan(x) terms**?\(\cos(2x) = \frac{1 – \tan^2x}{1 + \tan^2x}\)