- This topic has 1 reply, 1 voice, and was last updated 3 years, 2 months ago by .
Viewing 2 posts - 1 through 2 (of 2 total)
Viewing 2 posts - 1 through 2 (of 2 total)
- You must be logged in to reply to this topic.
Please explain.
Cathode: H+, Ag+
Anode: F–, OH–
Cathode Reaction: Ag+ (aq) + e– →Ag (s)
Anode Reaction: 4OH– (aq) – 4e– → 2H2O (l)+O2 (g)
Thus, the product at the anode is oxygen gas and at the cathode electrode is silver metal.