- This topic has 1 reply, 1 voice, and was last updated 2 years, 10 months ago by .

Viewing 2 posts - 1 through 2 (of 2 total)

Viewing 2 posts - 1 through 2 (of 2 total)

- You must be logged in to reply to this topic.

Home › Forums › Math › Using the quadratic formula to solve 2x^2 = 4x – 7, what are the values of x?

Tagged: algebra, quadratic expression, quadratic formula

- This topic has 1 reply, 1 voice, and was last updated 2 years, 10 months ago by suseelk.

Viewing 2 posts - 1 through 2 (of 2 total)

- AuthorPosts
- July 21, 2021 at 8:05 pm #10817
Can somebody please add the solution!

July 21, 2021 at 8:11 pm #10818::**Answer:**x = (2 ± √10 i)/2**Explanation :**

**Standard Quadratic Expression :**ax^2 + bx + c = 0

Using**quadratic formula**, expression for roots,

x = [ -b ± √(b2 – 4ac) ] / 2aBy comparing,

=> x = [ -(-4) ± √{(-4)2 – 4(2)(7)} ] / 2(2)

=> x = [ 4 ± √{16 – 56} ] / 4

=> x = [ 4 ± √(-40) ] / 4

=> x = [ 4 ± 2√10 i ] / 4

=> x = (2 ± √10i)/2Therefore, the roots of x are : (2 + √10 i)/2 and (2 – √10 i)/2

- This reply was modified 2 years, 10 months ago by ProtonsTalk.

- AuthorPosts

Viewing 2 posts - 1 through 2 (of 2 total)

- You must be logged in to reply to this topic.

Scroll to Top

Scroll to Top