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Home › Forums › Math › Using the quadratic formula to solve 2x^2 = 4x – 7, what are the values of x?
Tagged: algebra, quadratic expression, quadratic formula
Can somebody please add the solution!
Answer: x = (2 ± √10 i)/2
Explanation :
Standard Quadratic Expression : ax^2 + bx + c = 0
Using quadratic formula, expression for roots,
x = [ -b ± √(b2 – 4ac) ] / 2a
By comparing,
=> x = [ -(-4) ± √{(-4)2 – 4(2)(7)} ] / 2(2)
=> x = [ 4 ± √{16 – 56} ] / 4
=> x = [ 4 ± √(-40) ] / 4
=> x = [ 4 ± 2√10 i ] / 4
=> x = (2 ± √10i)/2
Therefore, the roots of x are : (2 + √10 i)/2 and (2 – √10 i)/2