The number of three digit numbers are divisible by 7 are 128.

Process to find It

Firstly you have to find the first and last three digit number divisible by 7.

An easy way to find these are

Firstly, Divide first three digit number 100 by 7 which gives 14 as quotient and 2 as remainder.

So, first three digit number divisible by 7 will be 7*(14+1) = 7*(14+1) = 105

Similarly, for last number, divide first four digit number by 7 i.e 1000/7 which gives 142 and remainder as 6.

So, last three digit number divisible by 7 is 7*(142) = 994.

So, first three digit divisible number = 7*(15)

So, last three digit divisible number = 7*(142)

So, the number of multiples will be from 15th multiple to 142nd multiple which is 128 multiples.

So, the number of three digit numbers which are divisible by 7 are 128.

You might also be interested in Divisibility Rules of 7

• This reply was modified 2 years, 4 months ago by ProtonsTalk.
• This reply was modified 2 years, 4 months ago by ProtonsTalk.