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Home › Forums › Physics › How many photons are contained in a flash of green light (525 nm) that contains 189 kJ of energy?
a) 5.67 x 10^23 photons
b) 2.01 x 10^24 photons
c) 4.99 x 10^23 photons
d) 1.25 x 10^31 photons
The correct answer is c) 4.99 x 10^23 photons
Explanation:
The energy of a photon is given as E = hf
where,
h = Planck’s constant = 6.626×10^-34 Js
f = frequency = c/x
c = speed of light = 3×10^8 m/s
x = wavelength = 525 nm = 525×10^-9 m
E = hc/x
=> E = 6.626×10^-34 × 3×10^8 / (525×10^-9)
=> E = 3.79×10^-19 J/Photon
=> E = 3.79×10^-22 kJ/Photon
And, 189 kJ/3.79×10^-22 kJ/photon = 4.99×10^23 photons.
So the number of photons is 4.99×10^23 photons.