Home Forums Physics How many photons are contained in a flash of green light (525 nm) that contains 189 kJ of energy?

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  • #9785
    Sai Teja
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      a) 5.67 x 10^23 photons
      b) 2.01 x 10^24 photons
      c) 4.99 x 10^23 photons
      d) 1.25 x 10^31 photons

      #9786
      elon musk
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        The correct answer is c) 4.99 x 10^23 photons

        Explanation:

        The energy of a photon is given as E = hf

        where,
        h = Planck’s constant = 6.626×10^-34 Js
        f = frequency = c/x
        c = speed of light = 3×10^8 m/s
        x = wavelength = 525 nm = 525×10^-9 m

        E = hc/x
        => E = 6.626×10^-34 × 3×10^8 / (525×10^-9)
        => E = 3.79×10^-19 J/Photon
        => E = 3.79×10^-22 kJ/Photon

        And, 189 kJ/3.79×10^-22 kJ/photon = 4.99×10^23 photons.

        So the number of photons is 4.99×10^23 photons.

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