- This topic has 1 reply, 1 voice, and was last updated 2 years, 11 months ago by .

Viewing 2 posts - 1 through 2 (of 2 total)

Viewing 2 posts - 1 through 2 (of 2 total)

- You must be logged in to reply to this topic.

Home › Forums › Math › For what values of m does the graph of y = mx^2 – 5x – 2 have no x-intercepts?

- This topic has 1 reply, 1 voice, and was last updated 2 years, 11 months ago by shilpav.

Viewing 2 posts - 1 through 2 (of 2 total)

- AuthorPosts
- July 19, 2021 at 7:26 pm #10316
Please add the solution.

July 19, 2021 at 7:27 pm #10318::**Answer:**The graph of y=mx^{2}-5x-2 has no x-intercepts for m<-25/8**Solution:**y=mx

^{2}-5x-2To get x-intercepts, y must be zero:

=> y=0

=> mx^{2}-5x-2=0We can solve this equation using the quadratic formula:

ax^{2}+bx+c=0; a=m, b=-5, c=-2=> x = [-b ± sqrt( b

^{2 }– 4ac) ] / (2a)

=> x = [-(-5) ± sqrt( (-5)^{2}– 4(m)(-2) )] / (2(m))

=> x = [5 ± sqrt(25 + 8m)] / (2m)This equation doesn’t have a solution (no x-intercepts) if:

25 + 8m < 0

=> 8m < -25

=> m < -25/8Hence, The graph of y=mx

^{2}-5x-2 has no x-intercepts for m < -25/8- This reply was modified 2 years, 11 months ago by ProtonsTalk.
- This reply was modified 2 years, 8 months ago by ProtonsTalk.

- AuthorPosts

Viewing 2 posts - 1 through 2 (of 2 total)

- You must be logged in to reply to this topic.

Scroll to Top

Scroll to Top