Home Forums Physics What is the system’s potential energy when its kinetic energy is equal to 34e? Reply To: What is the system’s potential energy when its kinetic energy is equal to 34e?

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hemanthk
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    Answers is 1 (kA^2)/8
    Explanation:
    Total energy= PEmax on the spring = KEmax of the object
    Total Energy= Kinetic Energy + Potential Energy
    Therefore, At v or x not maximum.

    Using the above one
    E= 3/4 E + PE (potential energy)
    PE = 1/4 E

    PEmax =E = 1/2 kA^2
    PE=E/4
    PE=(1/2)kA^2 / 4
    PE= kA^2/8

    • This reply was modified 2 years, 9 months ago by hemanthk.
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