Home Forums Physics What is the system’s potential energy when its kinetic energy is equal to 34e?

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  • #9836
    hemanthk
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      1.(kA^2)/8
      2.(kA^2)/2
      3.(kA^2)/4
      4.(kA^2)/6

      #9842
      hemanthk
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        Answers is 1 (kA^2)/8
        Explanation:
        Total energy= PEmax on the spring = KEmax of the object
        Total Energy= Kinetic Energy + Potential Energy
        Therefore, At v or x not maximum.

        Using the above one
        E= 3/4 E + PE (potential energy)
        PE = 1/4 E

        PEmax =E = 1/2 kA^2
        PE=E/4
        PE=(1/2)kA^2 / 4
        PE= kA^2/8

        • This reply was modified 2 years, 11 months ago by hemanthk.
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