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The number of three digit numbers are divisible by 7 are **128**.

**Process to find It**

Firstly you have to find the first and last three digit number divisible by 7.

An easy way to find these are

Firstly, Divide first three digit number 100 by 7 which gives 14 as quotient and 2 as remainder.

So, first three digit number divisible by 7 will be 7*(14+1) = 7*(14+1) = 105

Similarly, for last number, divide first four digit number by 7 i.e 1000/7 which gives 142 and remainder as 6.

So, last three digit number divisible by 7 is 7*(142) = 994.

So, first three digit divisible number = 7*(15)

So, last three digit divisible number = 7*(142)

So, the number of multiples will be from 15th multiple to 142nd multiple which is 128 multiples.

So, the number of three digit numbers which are divisible by 7 are **128**.

You might also be interested in Divisibility Rules of 7

- This reply was modified 2 years, 2 months ago by ProtonsTalk.
- This reply was modified 2 years, 2 months ago by ProtonsTalk.