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Please explain.
Cathode: H+, Ag+
Anode: F–, OH–
Cathode Reaction: Ag+ (aq) + e– →Ag (s)
Anode Reaction: 4OH– (aq) – 4e– → 2H2O (l)+O2 (g)
Thus, the product at the anode is oxygen gas and at the cathode electrode is silver metal.