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• #10824
shrutis
Participant

The structural level of protein least affected by disruption in hydrogen bonding is the primary level. Proteins are macromolecules and have four different levels of structure they are primary, secondary, tertiary, quaternary.Primary structure of the protein is formed by the covalent bond i.e., peptide bonds. hence, after disruption of hydrogen bond its structure will remain intact. Whereas secondary, tertiary and quaternary structure possess hydrogen bond.

#10833
shrutis
Participant

Ammonia (NH3) molecules effuse 1.28 times faster than carbon monoxide (CO) molecules.

Explanation:
The kinetic molecular theory tells us that

Vrms = √(3RT/MW) where Vrms is the root mean square velocity of an ideal gas. So Vrms is inversely proportional to MW and so will be the rate of effusion.

Comparing NH3 and CO we have:

rate(NH3)/rate(CO) = √MW(CO)/√MW(NH3) = √28.01/√17.03 = 1.28

rate(NH3) = 1.28 x rate(CO)

• This reply was modified 2 years, 8 months ago by ProtonsTalk.
#10147
shrutis
Participant

-6x^3 + x^2 –
In polynomial the degree and coefficient of x should be natural and 1.
Base must must not negative.

#10004
shrutis
Participant

Answer: Mendel’s law of independent assortment states that the genes are separated and inherited independently of each other into the gametes. The corn can be used to study the law if independent assortment as each kernel of the corn is its fruit. Thus, it is a result of sexual reproduction.

OR
(i)In case of corn, in addition to this there can be a pure line trait which can be found in corn.
(ii) However Mendel used Garden pea for his experiment ,we can use corn because it is similar to character with that of Garden pea.
(iii) While doing the experiment with corn we found out that there is independent and random assortment of the different gametes.

#10076
shrutis
Participant

It would be difficult to find the ideal CO2 level with a low light intensity because the plant will have a difficult time trying to survive.

It would be very hard considering with no light there’s no reaction.

If the temp were extremely hot or cold, then oxygen production would be near zero no matter what light intensity value you use

#10130
shrutis
Participant
#10140
shrutis
Participant

Given function: f(x) = 2x^6 – 2x^2 – 5.

In order to find the end behaviour of the graph, we need to find the degree of the given function and the leading coefficent.

Degree of the given function is the highest power of the variable.

We have variable x there.

Highest power of x is 6.

So, we can say:

Degree = 6 ( an even degree)

And leading coefficent is the coefficent of highest power term.

We have highest power term is 2x^6.

So, the leading coefficent is : 2 (Positive number)

For even degree and positive leading coefficent, end behaviour is

x –> ∞ f(x) = +∞

x–>-∞ f(x) = +∞

#9953
shrutis
Participant

Tempestt graphs a function that has a maximum located at (–4, 2)

=> for x = – 4 , the y = 2 is the maximum value
hence ( – 4 , 2) is the vertex
hence every point on graph would be less than 2 on y – axis for any x

It goes through (- 6, 6), has a vertex at (- 4, 2), and goes through -2, 6).
not possible as y = 6 > 2

It goes through (2, 6), has a vertex at (4, 2), and goes through (6, 6).
not possible as y = 6 > 2
it goes through (-6, -2), has a vertex at (- 4, 2), and goes through (-2, -2).
vertex (-4 , 2)
y < 2

This Could be her Graph

It goes through (2, -2), has a vertex at (4, 2), and goes through (6, -2).
not possible as vertex here is (4 , 2) instead of (-4,2)

Her Graph

On a coordinate plane, a parabola opens down it goes through (-6, -2), has a vertex at (- 4, 2), and goes through (-2, -2).

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