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    What is the radius of a circle whose equation is x2 + y2 + 8x – 6y + 21 = 0? units

    • This topic was modified 2 years, 1 month ago by ProtonsTalk.
    • This topic was modified 2 years, 1 month ago by ProtonsTalk.
    #20941
    ProtonsTalk
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      The radius of a circle whose equation is x2 + y2 + 8x – 6y + 21 = 0 is 5 units.

      We know that the general form of a circle is as follows.

      (x – a)2 + (y-b)2 = r2

      => x2 + y– 2ax – 2by + (a2 + b2 – r2) = 0

      And we know that radius = r = √(a2 +b2 )

      So, comparing the given equation and the general form of the equation.

      we get

      => -2ax = 8x => a = – 4

      => -2by = -6y => b = 3

      So, r = √((-4)2 +32 ) = √16 + 9 = √25 = 5

      So, the radius r of a circle whose equation is x2 + y2 + 8x – 6y + 21 = 0 is 5 units.

      • This reply was modified 2 years, 1 month ago by ProtonsTalk.
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