Home Forums Chemistry Calculate the percent ionization of ha in a 0.10 m solution.

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  • #9937
    hemanthk
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      Can somebody please add the solution!

      • This topic was modified 2 years, 9 months ago by hemanthk.
      #9947
      hemanthk
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        HA ==> H+ + A-
        So %-ionization = [H+]/[HA] x 100%
        Ka = [H+][A-]/[HA] = 3.2 x 10^-7
        Let [H+] = x. Then [A-] = x and [HA] = 0.10 – x.
        But x is so small .
        So that we can neglect and we can say that [HA] = 0.10.
        Ka = (x)(x)/(0.10) = 3.2 x 10^-7
        X^2 = 3.2 x 10^-8, so x = 1.8 x 10^-4 = [H+]
        %-Ionization = (1.8×10^-4)/(0.10) x 100%
        = 0.18%

        • This reply was modified 2 years, 9 months ago by hemanthk.
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